Base | Representation |
---|---|
bin | 10111011100100111000110… |
… | …101111000101000101100010 |
3 | 111112010021212000100222122121 |
4 | 113130213012233011011202 |
5 | 102004014211213240114 |
6 | 1003153121021254454 |
7 | 30502155365554465 |
oct | 2734470657050542 |
9 | 445107760328577 |
10 | 103121204040034 |
11 | 2a948503353084 |
12 | b6956b670442a |
13 | 457039843a51b |
14 | 1b67142d132dc |
15 | bdc644a51a24 |
hex | 5dc9c6bc5162 |
103121204040034 has 8 divisors (see below), whose sum is σ = 154959511279068. Its totient is φ = 51468033613680.
The previous prime is 103121204040007. The next prime is 103121204040119. The reversal of 103121204040034 is 430040402121301.
It can be written as a sum of positive squares in 2 ways, for example, as 84296912382225 + 18824291657809 = 9181335^2 + 4338697^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a junction number, because it is equal to n+sod(n) for n = 103121204039990 and 103121204040008.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 46284201777 + ... + 46284204004.
Almost surely, 2103121204040034 is an apocalyptic number.
103121204040034 is a deficient number, since it is larger than the sum of its proper divisors (51838307239034).
103121204040034 is an equidigital number, since it uses as much as digits as its factorization.
103121204040034 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 92568406340.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 103121204040034 its reverse (430040402121301), we get a palindrome (533161606161335).
The spelling of 103121204040034 in words is "one hundred three trillion, one hundred twenty-one billion, two hundred four million, forty thousand, thirty-four".
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