103121210013333 has 4 divisors (see below), whose sum is σ = 137494946684448. Its totient is φ = 68747473342220.

The previous prime is 103121210013307. The next prime is 103121210013337. The reversal of 103121210013333 is 333310012121301.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 103121210013333 - 2²⁰ = 103121208964757 is a prime.

It is a super-2 number, since 2×103121210013333² (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (103121210013337) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17186868335553 + ... + 17186868335558.

It is an arithmetic number, because the mean of its divisors is an integer number (34373736671112).

Almost surely, 2^{103121210013333} is an apocalyptic number.

It is an amenable number.

103121210013333 is a deficient number, since it is larger than the sum of its proper divisors (34373736671115).

103121210013333 is an equidigital number, since it uses as much as digits as its factorization.

103121210013333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 34373736671114.

The product of its (nonzero) digits is 972, while the sum is 24.

Adding to 103121210013333 its reverse (333310012121301), we get a palindrome (436431222134634).

The spelling of 103121210013333 in words is "one hundred three trillion, one hundred twenty-one billion, two hundred ten million, thirteen thousand, three hundred thirty-three".