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1031212113 = 3509675319
BaseRepresentation
bin111101011101110…
…000110001010001
32122212102000002020
4331131300301101
54102442241423
6250154242053
734361105211
oct7535606121
92585360066
101031212113
1148a101a18
12249426329
13135847aa9
149ad54241
15607e94e3
hex3d770c51

1031212113 has 8 divisors (see below), whose sum is σ = 1377652800. Its totient is φ = 686123088.

The previous prime is 1031212067. The next prime is 1031212139. The reversal of 1031212113 is 3112121301.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1031212113 - 222 = 1027017809 is a prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 1031212092 and 1031212101.

It is not an unprimeable number, because it can be changed into a prime (1031212183) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 336133 + ... + 339186.

It is an arithmetic number, because the mean of its divisors is an integer number (172206600).

Almost surely, 21031212113 is an apocalyptic number.

It is an amenable number.

1031212113 is a deficient number, since it is larger than the sum of its proper divisors (346440687).

1031212113 is an equidigital number, since it uses as much as digits as its factorization.

1031212113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 675831.

The product of its (nonzero) digits is 36, while the sum is 15.

The square root of 1031212113 is about 32112.4915414547. The cubic root of 1031212113 is about 1010.2976324415.

Adding to 1031212113 its reverse (3112121301), we get a palindrome (4143333414).

The spelling of 1031212113 in words is "one billion, thirty-one million, two hundred twelve thousand, one hundred thirteen".

Divisors: 1 3 509 1527 675319 2025957 343737371 1031212113