Base | Representation |
---|---|
bin | 1001011000001111101001… |
… | …0101010100110000011001 |
3 | 1100111211101110201102111201 |
4 | 2112003322111110300121 |
5 | 2322423211034420231 |
6 | 33533153445554201 |
7 | 2113011660454333 |
oct | 226037225246031 |
9 | 40454343642451 |
10 | 10312121404441 |
11 | 331638977293a |
12 | 11a6684715961 |
13 | 59a576317b9c |
14 | 279176052453 |
15 | 12d396854161 |
hex | 960fa554c19 |
10312121404441 has 2 divisors, whose sum is σ = 10312121404442. Its totient is φ = 10312121404440.
The previous prime is 10312121404433. The next prime is 10312121404493. The reversal of 10312121404441 is 14440412121301.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 8061221314441 + 2250900090000 = 2839229^2 + 1500300^2 .
It is a cyclic number.
It is not a de Polignac number, because 10312121404441 - 23 = 10312121404433 is a prime.
It is not a weakly prime, because it can be changed into another prime (10312121404141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5156060702220 + 5156060702221.
It is an arithmetic number, because the mean of its divisors is an integer number (5156060702221).
Almost surely, 210312121404441 is an apocalyptic number.
It is an amenable number.
10312121404441 is a deficient number, since it is larger than the sum of its proper divisors (1).
10312121404441 is an equidigital number, since it uses as much as digits as its factorization.
10312121404441 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3072, while the sum is 28.
Adding to 10312121404441 its reverse (14440412121301), we get a palindrome (24752533525742).
The spelling of 10312121404441 in words is "ten trillion, three hundred twelve billion, one hundred twenty-one million, four hundred four thousand, four hundred forty-one".
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