Search a number
-
+
10312130052101 is a prime number
BaseRepresentation
bin1001011000001111101011…
…0110010100000000000101
31100111211102001222202212102
42112003322312110000011
52322423220243131401
633533154355201445
72113012124122223
oct226037266240005
940454361882772
1010312130052101
113316393639a69
1211a66875a6285
1359a578055047
14279177263b13
1512d3974b156b
hex960fad94005

10312130052101 has 2 divisors, whose sum is σ = 10312130052102. Its totient is φ = 10312130052100.

The previous prime is 10312130052061. The next prime is 10312130052113. The reversal of 10312130052101 is 10125003121301.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5679308596900 + 4632821455201 = 2383130^2 + 2152399^2 .

It is a cyclic number.

It is not a de Polignac number, because 10312130052101 - 238 = 10037252145157 is a prime.

It is a super-2 number, since 2×103121300521012 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10312130052131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5156065026050 + 5156065026051.

It is an arithmetic number, because the mean of its divisors is an integer number (5156065026051).

Almost surely, 210312130052101 is an apocalyptic number.

It is an amenable number.

10312130052101 is a deficient number, since it is larger than the sum of its proper divisors (1).

10312130052101 is an equidigital number, since it uses as much as digits as its factorization.

10312130052101 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 180, while the sum is 20.

Adding to 10312130052101 its reverse (10125003121301), we get a palindrome (20437133173402).

The spelling of 10312130052101 in words is "ten trillion, three hundred twelve billion, one hundred thirty million, fifty-two thousand, one hundred one".