10312140121 has 4 divisors (see below), whose sum is σ = 10313435700. Its totient is φ = 10310844544.

The previous prime is 10312140119. The next prime is 10312140151. The reversal of 10312140121 is 12104121301.

10312140121 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 3809975625 + 6502164496 = 61725^2 + 80636^2 .

It is a cyclic number.

It is not a de Polignac number, because 10312140121 - 2¹ = 10312140119 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10312140095 and 10312140104.

It is not an unprimeable number, because it can be changed into a prime (10312140151) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 635776 + ... + 651793.

It is an arithmetic number, because the mean of its divisors is an integer number (2578358925).

Almost surely, 2^10312140121 is an apocalyptic number.

It is an amenable number.

10312140121 is a deficient number, since it is larger than the sum of its proper divisors (1295579).

10312140121 is an equidigital number, since it uses as much as digits as its factorization.

10312140121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1295578.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 10312140121 its reverse (12104121301), we get a palindrome (22416261422).

The spelling of 10312140121 in words is "ten billion, three hundred twelve million, one hundred forty thousand, one hundred twenty-one".