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1031230010011 = 1270381180037
BaseRepresentation
bin11110000000110100001…
…10010011001010011011
310122120210012012022101111
433000122012103022123
5113343424340310021
62105423542001151
7134334561312625
oct17003206231233
93576705168344
101031230010011
11368384502723
12147a38a161b7
13763244317c6
1437ca9d93c15
151bc583578e1
hexf01a19329b

1031230010011 has 4 divisors (see below), whose sum is σ = 1031311202752. Its totient is φ = 1031148817272.

The previous prime is 1031230009951. The next prime is 1031230010081. The reversal of 1031230010011 is 1100100321301.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1031230010011 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1031230009973 and 1031230010000.

It is not an unprimeable number, because it can be changed into a prime (1031230010081) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 40577316 + ... + 40602721.

It is an arithmetic number, because the mean of its divisors is an integer number (257827800688).

Almost surely, 21031230010011 is an apocalyptic number.

1031230010011 is a deficient number, since it is larger than the sum of its proper divisors (81192741).

1031230010011 is an equidigital number, since it uses as much as digits as its factorization.

1031230010011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 81192740.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 1031230010011 its reverse (1100100321301), we get a palindrome (2131330331312).

The spelling of 1031230010011 in words is "one trillion, thirty-one billion, two hundred thirty million, ten thousand, eleven".

Divisors: 1 12703 81180037 1031230010011