Base | Representation |
---|---|
bin | 1001011000010000010110… |
… | …1100011011100110001001 |
3 | 1100111211212202101020202021 |
4 | 2112010011230123212021 |
5 | 2322424103333324040 |
6 | 33533224415204441 |
7 | 2113016463550114 |
oct | 226040554334611 |
9 | 40454782336667 |
10 | 10312312011145 |
11 | 331647731a541 |
12 | 11a6718516721 |
13 | 59a5a6963811 |
14 | 2791934ab57b |
15 | 12d3a845524a |
hex | 96105b1b989 |
10312312011145 has 8 divisors (see below), whose sum is σ = 12378606818760. Its totient is φ = 8247294672000.
The previous prime is 10312312011139. The next prime is 10312312011151. The reversal of 10312312011145 is 54111021321301.
It is an interprime number because it is at equal distance from previous prime (10312312011139) and next prime (10312312011151).
It can be written as a sum of positive squares in 4 ways, for example, as 667337046649 + 9644974964496 = 816907^2 + 3105636^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a de Polignac number, because none of the positive numbers 2k-10312312011145 is a prime.
It is a super-2 number, since 2×103123120111452 (a number of 27 digits) contains 22 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 319349356 + ... + 319381645.
It is an arithmetic number, because the mean of its divisors is an integer number (1547325852345).
Almost surely, 210312312011145 is an apocalyptic number.
It is an amenable number.
10312312011145 is a deficient number, since it is larger than the sum of its proper divisors (2066294807615).
10312312011145 is an equidigital number, since it uses as much as digits as its factorization.
10312312011145 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 638734235.
The product of its (nonzero) digits is 720, while the sum is 25.
Adding to 10312312011145 its reverse (54111021321301), we get a palindrome (64423333332446).
The spelling of 10312312011145 in words is "ten trillion, three hundred twelve billion, three hundred twelve million, eleven thousand, one hundred forty-five".
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