Base | Representation |
---|---|
bin | 11110000000110101110… |
… | …00101110110010000111 |
3 | 10122120211010001222021102 |
4 | 33000122320232302013 |
5 | 113343441231332333 |
6 | 2105425133210315 |
7 | 134335111554104 |
oct | 17003270566207 |
9 | 3576733058242 |
10 | 1031243230343 |
11 | 368390a12317 |
12 | 147a4133099b |
13 | 763270b00a1 |
14 | 37caba35aab |
15 | 1bc595b9ae8 |
hex | f01ae2ec87 |
1031243230343 has 2 divisors, whose sum is σ = 1031243230344. Its totient is φ = 1031243230342.
The previous prime is 1031243230337. The next prime is 1031243230357. The reversal of 1031243230343 is 3430323421301.
1031243230343 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1031243230343 - 218 = 1031242968199 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1031243230643) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 515621615171 + 515621615172.
It is an arithmetic number, because the mean of its divisors is an integer number (515621615172).
Almost surely, 21031243230343 is an apocalyptic number.
1031243230343 is a deficient number, since it is larger than the sum of its proper divisors (1).
1031243230343 is an equidigital number, since it uses as much as digits as its factorization.
1031243230343 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15552, while the sum is 29.
Adding to 1031243230343 its reverse (3430323421301), we get a palindrome (4461566651644).
The spelling of 1031243230343 in words is "one trillion, thirty-one billion, two hundred forty-three million, two hundred thirty thousand, three hundred forty-three".
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