1031243314111 has 4 divisors (see below), whose sum is σ = 1034496447912. Its totient is φ = 1027990180312.

The previous prime is 1031243314109. The next prime is 1031243314183. The reversal of 1031243314111 is 1114133421301.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1031243314111 - 2¹ = 1031243314109 is a prime.

It is a super-2 number, since 2×1031243314111² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1031243318111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1626566425 + ... + 1626567058.

It is an arithmetic number, because the mean of its divisors is an integer number (258624111978).

Almost surely, 2^{1031243314111} is an apocalyptic number.

1031243314111 is a deficient number, since it is larger than the sum of its proper divisors (3253133801).

1031243314111 is an equidigital number, since it uses as much as digits as its factorization.

1031243314111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3253133800.

The product of its (nonzero) digits is 864, while the sum is 25.

Adding to 1031243314111 its reverse (1114133421301), we get a palindrome (2145376735412).

The spelling of 1031243314111 in words is "one trillion, thirty-one billion, two hundred forty-three million, three hundred fourteen thousand, one hundred eleven".