Base | Representation |
---|---|
bin | 1001011000010001011110… |
… | …1010101011101100101111 |
3 | 1100111212122202202122021202 |
4 | 2112010113222223230233 |
5 | 2322430213031331303 |
6 | 33533314350120115 |
7 | 2113030114535633 |
oct | 226042752535457 |
9 | 40455582678252 |
10 | 10312613542703 |
11 | 331661154a67a |
12 | 11a67a14b003b |
13 | 59a624279764 |
14 | 2791c155cdc3 |
15 | 12d3c4b67c88 |
hex | 96117aabb2f |
10312613542703 has 2 divisors, whose sum is σ = 10312613542704. Its totient is φ = 10312613542702.
The previous prime is 10312613542591. The next prime is 10312613542709. The reversal of 10312613542703 is 30724531621301.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10312613542703 - 210 = 10312613541679 is a prime.
It is a super-2 number, since 2×103126135427032 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10312613542709) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5156306771351 + 5156306771352.
It is an arithmetic number, because the mean of its divisors is an integer number (5156306771352).
Almost surely, 210312613542703 is an apocalyptic number.
10312613542703 is a deficient number, since it is larger than the sum of its proper divisors (1).
10312613542703 is an equidigital number, since it uses as much as digits as its factorization.
10312613542703 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 90720, while the sum is 38.
The spelling of 10312613542703 in words is "ten trillion, three hundred twelve billion, six hundred thirteen million, five hundred forty-two thousand, seven hundred three".
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