Base | Representation |
---|---|
bin | 1001011000010001100101… |
… | …0000100101000111111111 |
3 | 1100111212201122000201221012 |
4 | 2112010121100211013333 |
5 | 2322430241401120323 |
6 | 33533321142425435 |
7 | 2113030560560531 |
oct | 226043120450777 |
9 | 40455648021835 |
10 | 10312640254463 |
11 | 3316625634608 |
12 | 11a67aa43227b |
13 | 59a62996cb31 |
14 | 2791c4d13851 |
15 | 12d3c7192678 |
hex | 961194251ff |
10312640254463 has 2 divisors, whose sum is σ = 10312640254464. Its totient is φ = 10312640254462.
The previous prime is 10312640254459. The next prime is 10312640254513. The reversal of 10312640254463 is 36445204621301.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10312640254463 - 22 = 10312640254459 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 10312640254463.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10312640250463) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5156320127231 + 5156320127232.
It is an arithmetic number, because the mean of its divisors is an integer number (5156320127232).
Almost surely, 210312640254463 is an apocalyptic number.
10312640254463 is a deficient number, since it is larger than the sum of its proper divisors (1).
10312640254463 is an equidigital number, since it uses as much as digits as its factorization.
10312640254463 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 414720, while the sum is 41.
Adding to 10312640254463 its reverse (36445204621301), we get a palindrome (46757844875764).
The spelling of 10312640254463 in words is "ten trillion, three hundred twelve billion, six hundred forty million, two hundred fifty-four thousand, four hundred sixty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.082 sec. • engine limits •