1031300044111 has 2 divisors, whose sum is σ = 1031300044112. Its totient is φ = 1031300044110.

The previous prime is 1031300044081. The next prime is 1031300044121. The reversal of 1031300044111 is 1114400031301.

It is a strong prime.

It is an emirp because it is prime and its reverse (1114400031301) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1031300044111 - 2⁵ = 1031300044079 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1031300044121) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 515650022055 + 515650022056.

It is an arithmetic number, because the mean of its divisors is an integer number (515650022056).

Almost surely, 2^{1031300044111} is an apocalyptic number.

1031300044111 is a deficient number, since it is larger than the sum of its proper divisors (1).

1031300044111 is an equidigital number, since it uses as much as digits as its factorization.

1031300044111 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 1031300044111 its reverse (1114400031301), we get a palindrome (2145700075412).

The spelling of 1031300044111 in words is "one trillion, thirty-one billion, three hundred million, forty-four thousand, one hundred eleven".