1031300121222 has 40 divisors (see below), whose sum is σ = 2641001371536. Its totient is φ = 294657177168.

The previous prime is 1031300121199. The next prime is 1031300121259. The reversal of 1031300121222 is 2221210031301.

1031300121222 is a `hidden beast` number, since 10 + 313 + 0 + 0 + 121 + 222 = 666.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 1031300121195 and 1031300121204.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 454716733 + ... + 454719000.

Almost surely, 2^{1031300121222} is an apocalyptic number.

1031300121222 is an abundant number, since it is smaller than the sum of its proper divisors (1609701250314).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1031300121222 is an equidigital number, since it uses as much as digits as its factorization.

1031300121222 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 909435754 (or 909435745 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 18.

Adding to 1031300121222 its reverse (2221210031301), we get a palindrome (3252510152523).

The spelling of 1031300121222 in words is "one trillion, thirty-one billion, three hundred million, one hundred twenty-one thousand, two hundred twenty-two".