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1031300122099 = 1379330778623
BaseRepresentation
bin11110000000111100100…
…01110000010111110011
310122120222002010101002111
433000132101300113303
5113344100312401344
62105434524430151
7134336402254222
oct17003621602763
93576862111074
101031300122099
1136841003a9a5
12147a583a8357
1376335b0c350
1437cb5404cb9
151bc5e5a6834
hexf01e4705f3

1031300122099 has 4 divisors (see below), whose sum is σ = 1110630900736. Its totient is φ = 951969343464.

The previous prime is 1031300122091. The next prime is 1031300122129. The reversal of 1031300122099 is 9902210031301.

1031300122099 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1031300122099 - 23 = 1031300122091 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1031300122099.

It is not an unprimeable number, because it can be changed into a prime (1031300122091) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 39665389299 + ... + 39665389324.

It is an arithmetic number, because the mean of its divisors is an integer number (277657725184).

Almost surely, 21031300122099 is an apocalyptic number.

1031300122099 is a deficient number, since it is larger than the sum of its proper divisors (79330778637).

1031300122099 is an equidigital number, since it uses as much as digits as its factorization.

1031300122099 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 79330778636.

The product of its (nonzero) digits is 2916, while the sum is 31.

The spelling of 1031300122099 in words is "one trillion, thirty-one billion, three hundred million, one hundred twenty-two thousand, ninety-nine".

Divisors: 1 13 79330778623 1031300122099