Base | Representation |
---|---|
bin | 10011001101011001… |
… | …11110110101001001 |
3 | 222121201201210120122 |
4 | 21212230332311021 |
5 | 132110112033223 |
6 | 4423203233025 |
7 | 513365034065 |
oct | 114654766511 |
9 | 28551653518 |
10 | 10313002313 |
11 | 441246a309 |
12 | 1bb9978775 |
13 | c847bb543 |
14 | 6db95caa5 |
15 | 4055d95c8 |
hex | 266b3ed49 |
10313002313 has 2 divisors, whose sum is σ = 10313002314. Its totient is φ = 10313002312.
The previous prime is 10313002277. The next prime is 10313002321. The reversal of 10313002313 is 31320031301.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10311996304 + 1006009 = 101548^2 + 1003^2 .
It is a cyclic number.
It is not a de Polignac number, because 10313002313 - 210 = 10313001289 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 10313002291 and 10313002300.
It is not a weakly prime, because it can be changed into another prime (10313002373) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5156501156 + 5156501157.
It is an arithmetic number, because the mean of its divisors is an integer number (5156501157).
Almost surely, 210313002313 is an apocalyptic number.
It is an amenable number.
10313002313 is a deficient number, since it is larger than the sum of its proper divisors (1).
10313002313 is an equidigital number, since it uses as much as digits as its factorization.
10313002313 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 162, while the sum is 17.
Adding to 10313002313 its reverse (31320031301), we get a palindrome (41633033614).
The spelling of 10313002313 in words is "ten billion, three hundred thirteen million, two thousand, three hundred thirteen".
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