103131102113133 has 4 divisors (see below), whose sum is σ = 137508136150848. Its totient is φ = 68754068075420.

The previous prime is 103131102113119. The next prime is 103131102113159. The reversal of 103131102113133 is 331311201131301.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 103131102113133 - 2¹² = 103131102109037 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (103131102113033) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17188517018853 + ... + 17188517018858.

It is an arithmetic number, because the mean of its divisors is an integer number (34377034037712).

Almost surely, 2^{103131102113133} is an apocalyptic number.

It is an amenable number.

103131102113133 is a deficient number, since it is larger than the sum of its proper divisors (34377034037715).

103131102113133 is an equidigital number, since it uses as much as digits as its factorization.

103131102113133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 34377034037714.

The product of its (nonzero) digits is 486, while the sum is 24.

Adding to 103131102113133 its reverse (331311201131301), we get a palindrome (434442303244434).

The spelling of 103131102113133 in words is "one hundred three trillion, one hundred thirty-one billion, one hundred two million, one hundred thirteen thousand, one hundred thirty-three".