Base | Representation |
---|---|
bin | 111101011110001… |
… | …000111100001111 |
3 | 2122212121000220010 |
4 | 331132020330033 |
5 | 4103003423434 |
6 | 250200324303 |
7 | 34361666646 |
oct | 7536107417 |
9 | 2585530803 |
10 | 1031311119 |
11 | 48a16a343 |
12 | 249473693 |
13 | 135880b87 |
14 | 9ad7c35d |
15 | 608189e9 |
hex | 3d788f0f |
1031311119 has 4 divisors (see below), whose sum is σ = 1375081496. Its totient is φ = 687540744.
The previous prime is 1031311093. The next prime is 1031311121. The reversal of 1031311119 is 9111131301.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 9111131301 = 3 ⋅3037043767.
It is not a de Polignac number, because 1031311119 - 215 = 1031278351 is a prime.
It is a super-2 number, since 2×10313111192 = 2127205248346064322, which contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1031311095 and 1031311104.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1031311199) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 171885184 + ... + 171885189.
It is an arithmetic number, because the mean of its divisors is an integer number (343770374).
Almost surely, 21031311119 is an apocalyptic number.
1031311119 is a deficient number, since it is larger than the sum of its proper divisors (343770377).
1031311119 is an equidigital number, since it uses as much as digits as its factorization.
1031311119 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 343770376.
The product of its (nonzero) digits is 81, while the sum is 21.
The square root of 1031311119 is about 32114.0330541027. The cubic root of 1031311119 is about 1010.3299640783.
The spelling of 1031311119 in words is "one billion, thirty-one million, three hundred eleven thousand, one hundred nineteen".
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