Base | Representation |
---|---|
bin | 11110000000111110000… |
… | …11101001101101100111 |
3 | 10122120222222201220101010 |
4 | 33000133003221231213 |
5 | 113344112134431043 |
6 | 2105440113033303 |
7 | 134336621402136 |
oct | 17003703515547 |
9 | 3576888656333 |
10 | 1031313202023 |
11 | 368417464055 |
12 | 147a60855833 |
13 | 7633873ba50 |
14 | 37cb704b91d |
15 | 1bc607dc133 |
hex | f01f0e9b67 |
1031313202023 has 16 divisors (see below), whose sum is σ = 1481216448096. Its totient is φ = 634501507200.
The previous prime is 1031313202019. The next prime is 1031313202069. The reversal of 1031313202023 is 3202023131301.
It is not a de Polignac number, because 1031313202023 - 22 = 1031313202019 is a prime.
It is a super-2 number, since 2×10313132020232 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1031313202093) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3018528 + ... + 3342773.
It is an arithmetic number, because the mean of its divisors is an integer number (92576028006).
Almost surely, 21031313202023 is an apocalyptic number.
1031313202023 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
1031313202023 is a deficient number, since it is larger than the sum of its proper divisors (449903246073).
1031313202023 is a wasteful number, since it uses less digits than its factorization.
1031313202023 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6365474.
The product of its (nonzero) digits is 648, while the sum is 21.
Adding to 1031313202023 its reverse (3202023131301), we get a palindrome (4233336333324).
The spelling of 1031313202023 in words is "one trillion, thirty-one billion, three hundred thirteen million, two hundred two thousand, twenty-three".
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