Base | Representation |
---|---|
bin | 1001011000010011101010… |
… | …1000111111110011100011 |
3 | 1100111221011122212011112212 |
4 | 2112010322220333303203 |
5 | 2322432413234201311 |
6 | 33533452510312335 |
7 | 2113050501114212 |
oct | 226047250776343 |
9 | 40457148764485 |
10 | 10313200303331 |
11 | 3316892785612 |
12 | 11a6925ab86ab |
13 | 59a6b89bb1b3 |
14 | 27923945b079 |
15 | 12d40b41cc8b |
hex | 9613aa3fce3 |
10313200303331 has 2 divisors, whose sum is σ = 10313200303332. Its totient is φ = 10313200303330.
The previous prime is 10313200303271. The next prime is 10313200303339. The reversal of 10313200303331 is 13330300231301.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-10313200303331 is a prime.
It is a super-2 number, since 2×103132003033312 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 10313200303297 and 10313200303306.
It is not a weakly prime, because it can be changed into another prime (10313200303339) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5156600151665 + 5156600151666.
It is an arithmetic number, because the mean of its divisors is an integer number (5156600151666).
Almost surely, 210313200303331 is an apocalyptic number.
10313200303331 is a deficient number, since it is larger than the sum of its proper divisors (1).
10313200303331 is an equidigital number, since it uses as much as digits as its factorization.
10313200303331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1458, while the sum is 23.
Adding to 10313200303331 its reverse (13330300231301), we get a palindrome (23643500534632).
The spelling of 10313200303331 in words is "ten trillion, three hundred thirteen billion, two hundred million, three hundred three thousand, three hundred thirty-one".
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