Base | Representation |
---|---|
bin | 10111011100110001001011… |
… | …011110111110011110001111 |
3 | 111112011022202212121201211112 |
4 | 113130301023132332132033 |
5 | 102004203334401413314 |
6 | 1003202110233042235 |
7 | 30503020424342423 |
oct | 2734611336763617 |
9 | 445138685551745 |
10 | 103132021122959 |
11 | 2a952054306634 |
12 | b69781525637b |
13 | 45714004ac2ca |
14 | 1b6788b7aab83 |
15 | bdca7950d43e |
hex | 5dcc4b7be78f |
103132021122959 has 2 divisors, whose sum is σ = 103132021122960. Its totient is φ = 103132021122958.
The previous prime is 103132021122931. The next prime is 103132021122979. The reversal of 103132021122959 is 959221120231301.
It is a strong prime.
It is an emirp because it is prime and its reverse (959221120231301) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 103132021122959 - 220 = 103132020074383 is a prime.
It is a super-2 number, since 2×1031320211229592 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (103132021122979) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51566010561479 + 51566010561480.
It is an arithmetic number, because the mean of its divisors is an integer number (51566010561480).
Almost surely, 2103132021122959 is an apocalyptic number.
103132021122959 is a deficient number, since it is larger than the sum of its proper divisors (1).
103132021122959 is an equidigital number, since it uses as much as digits as its factorization.
103132021122959 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 58320, while the sum is 41.
The spelling of 103132021122959 in words is "one hundred three trillion, one hundred thirty-two billion, twenty-one million, one hundred twenty-two thousand, nine hundred fifty-nine".
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