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1031321067809 is a prime number
BaseRepresentation
bin11110000000111111000…
…01101010000100100001
310122121000112112112012112
433000133201222010201
5113344121143132214
62105440553405105
7134340045302354
oct17003741520441
93577015475175
101031321067809
113684209467aa
12147a63409795
137633a264066
1437cb80d829b
151bc61342a3e
hexf01f86a121

1031321067809 has 2 divisors, whose sum is σ = 1031321067810. Its totient is φ = 1031321067808.

The previous prime is 1031321067793. The next prime is 1031321067823. The reversal of 1031321067809 is 9087601231301.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 603830014225 + 427491053584 = 777065^2 + 653828^2 .

It is a cyclic number.

It is not a de Polignac number, because 1031321067809 - 24 = 1031321067793 is a prime.

It is not a weakly prime, because it can be changed into another prime (1031321067859) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 515660533904 + 515660533905.

It is an arithmetic number, because the mean of its divisors is an integer number (515660533905).

Almost surely, 21031321067809 is an apocalyptic number.

It is an amenable number.

1031321067809 is a deficient number, since it is larger than the sum of its proper divisors (1).

1031321067809 is an equidigital number, since it uses as much as digits as its factorization.

1031321067809 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54432, while the sum is 41.

The spelling of 1031321067809 in words is "one trillion, thirty-one billion, three hundred twenty-one million, sixty-seven thousand, eight hundred nine".