Base | Representation |
---|---|
bin | 1001011000010011110000… |
… | …0000011010111011011101 |
3 | 1100111221020020222111121211 |
4 | 2112010330000122323131 |
5 | 2322432440121032312 |
6 | 33533455045424421 |
7 | 2113051166654356 |
oct | 226047400327335 |
9 | 40457206874554 |
10 | 10313223220957 |
11 | 33168a47089a8 |
12 | 11a693170b111 |
13 | 59a6c0683617 |
14 | 27923c504d2d |
15 | 12d40d4483a7 |
hex | 9613c01aedd |
10313223220957 has 2 divisors, whose sum is σ = 10313223220958. Its totient is φ = 10313223220956.
The previous prime is 10313223220889. The next prime is 10313223220967. The reversal of 10313223220957 is 75902232231301.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10311330187876 + 1893033081 = 3211126^2 + 43509^2 .
It is a cyclic number.
It is not a de Polignac number, because 10313223220957 - 27 = 10313223220829 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10313223220967) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5156611610478 + 5156611610479.
It is an arithmetic number, because the mean of its divisors is an integer number (5156611610479).
Almost surely, 210313223220957 is an apocalyptic number.
It is an amenable number.
10313223220957 is a deficient number, since it is larger than the sum of its proper divisors (1).
10313223220957 is an equidigital number, since it uses as much as digits as its factorization.
10313223220957 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 136080, while the sum is 40.
The spelling of 10313223220957 in words is "ten trillion, three hundred thirteen billion, two hundred twenty-three million, two hundred twenty thousand, nine hundred fifty-seven".
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