103140040433 has 2 divisors, whose sum is σ = 103140040434. Its totient is φ = 103140040432.

The previous prime is 103140040429. The next prime is 103140040453. The reversal of 103140040433 is 334040041301.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 98952397489 + 4187642944 = 314567^2 + 64712^2 .

It is a cyclic number.

It is not a de Polignac number, because 103140040433 - 2² = 103140040429 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 103140040399 and 103140040408.

It is not a weakly prime, because it can be changed into another prime (103140040403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51570020216 + 51570020217.

It is an arithmetic number, because the mean of its divisors is an integer number (51570020217).

Almost surely, 2^103140040433 is an apocalyptic number.

It is an amenable number.

103140040433 is a deficient number, since it is larger than the sum of its proper divisors (1).

103140040433 is an equidigital number, since it uses as much as digits as its factorization.

103140040433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1728, while the sum is 23.

Adding to 103140040433 its reverse (334040041301), we get a palindrome (437180081734).

The spelling of 103140040433 in words is "one hundred three billion, one hundred forty million, forty thousand, four hundred thirty-three".