1031411432133 has 12 divisors (see below), whose sum is σ = 1490612804928. Its totient is φ = 687240102120.

The previous prime is 1031411432119. The next prime is 1031411432147. The reversal of 1031411432133 is 3312341141301.

1031411432133 is a `hidden beast` number, since 1 + 0 + 31 + 411 + 4 + 3 + 213 + 3 = 666.

1031411432133 is digitally balanced in base 2 and base 4, because in such bases it contains all the possibile digits an equal number of times.

It is an interprime number because it is at equal distance from previous prime (1031411432119) and next prime (1031411432147).

It is not a de Polignac number, because 1031411432133 - 2¹⁰ = 1031411431109 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1031411432097 and 1031411432106.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1031411432533) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 30608835 + ... + 30642512.

It is an arithmetic number, because the mean of its divisors is an integer number (124217733744).

Almost surely, 2^{1031411432133} is an apocalyptic number.

It is an amenable number.

1031411432133 is a deficient number, since it is larger than the sum of its proper divisors (459201372795).

1031411432133 is a wasteful number, since it uses less digits than its factorization.

1031411432133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 61253224 (or 61253221 counting only the distinct ones).

The product of its (nonzero) digits is 2592, while the sum is 27.

Adding to 1031411432133 its reverse (3312341141301), we get a palindrome (4343752573434).

The spelling of 1031411432133 in words is "one trillion, thirty-one billion, four hundred eleven million, four hundred thirty-two thousand, one hundred thirty-three".