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10314121423 is a prime number
BaseRepresentation
bin10011001101100010…
…10000000011001111
3222121210211122201011
421212301100003033
5132110403341143
64423243230051
7513410404564
oct114661200317
928553748634
1010314121423
1144130640a1
121bba218327
13c84ac0a38
146dbb7086b
1540575ae9d
hex266c500cf

10314121423 has 2 divisors, whose sum is σ = 10314121424. Its totient is φ = 10314121422.

The previous prime is 10314121387. The next prime is 10314121429. The reversal of 10314121423 is 32412141301.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 10314121423 - 225 = 10280566991 is a prime.

It is a super-2 number, since 2×103141214232 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 10314121394 and 10314121403.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10314121429) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5157060711 + 5157060712.

It is an arithmetic number, because the mean of its divisors is an integer number (5157060712).

Almost surely, 210314121423 is an apocalyptic number.

10314121423 is a deficient number, since it is larger than the sum of its proper divisors (1).

10314121423 is an equidigital number, since it uses as much as digits as its factorization.

10314121423 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 576, while the sum is 22.

Adding to 10314121423 its reverse (32412141301), we get a palindrome (42726262724).

The spelling of 10314121423 in words is "ten billion, three hundred fourteen million, one hundred twenty-one thousand, four hundred twenty-three".