Base | Representation |
---|---|
bin | 110000000001110110… |
… | …0111111101110001101 |
3 | 100212020002122001111011 |
4 | 1200003230333232031 |
5 | 3142213140421333 |
6 | 115214340525221 |
7 | 10310636641156 |
oct | 1400354775615 |
9 | 325202561434 |
10 | 103141342093 |
11 | 3a818664999 |
12 | 17ba59b0811 |
13 | 995958114a |
14 | 4dc633a92d |
15 | 2a39dec9cd |
hex | 1803b3fb8d |
103141342093 has 2 divisors, whose sum is σ = 103141342094. Its totient is φ = 103141342092.
The previous prime is 103141342063. The next prime is 103141342151. The reversal of 103141342093 is 390243141301.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 66735938889 + 36405403204 = 258333^2 + 190802^2 .
It is a cyclic number.
It is not a de Polignac number, because 103141342093 - 25 = 103141342061 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (103141342063) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51570671046 + 51570671047.
It is an arithmetic number, because the mean of its divisors is an integer number (51570671047).
Almost surely, 2103141342093 is an apocalyptic number.
It is an amenable number.
103141342093 is a deficient number, since it is larger than the sum of its proper divisors (1).
103141342093 is an equidigital number, since it uses as much as digits as its factorization.
103141342093 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7776, while the sum is 31.
Adding to 103141342093 its reverse (390243141301), we get a palindrome (493384483394).
The spelling of 103141342093 in words is "one hundred three billion, one hundred forty-one million, three hundred forty-two thousand, ninety-three".
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