Base | Representation |
---|---|
bin | 10011001101100011… |
… | …01101000001111001 |
3 | 222121211001200112101 |
4 | 21212301231001321 |
5 | 132110421140441 |
6 | 4423245543401 |
7 | 513411410623 |
oct | 114661550171 |
9 | 28554050471 |
10 | 10314240121 |
11 | 4413135299 |
12 | 1bba274b61 |
13 | c84b32a83 |
14 | 6dbba1c13 |
15 | 405781231 |
hex | 266c6d079 |
10314240121 has 2 divisors, whose sum is σ = 10314240122. Its totient is φ = 10314240120.
The previous prime is 10314240043. The next prime is 10314240143. The reversal of 10314240121 is 12104241301.
10314240121 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8662955625 + 1651284496 = 93075^2 + 40636^2 .
It is a cyclic number.
It is not a de Polignac number, because 10314240121 - 221 = 10312142969 is a prime.
It is not a weakly prime, because it can be changed into another prime (10314240191) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5157120060 + 5157120061.
It is an arithmetic number, because the mean of its divisors is an integer number (5157120061).
Almost surely, 210314240121 is an apocalyptic number.
It is an amenable number.
10314240121 is a deficient number, since it is larger than the sum of its proper divisors (1).
10314240121 is an equidigital number, since it uses as much as digits as its factorization.
10314240121 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 192, while the sum is 19.
Adding to 10314240121 its reverse (12104241301), we get a palindrome (22418481422).
The spelling of 10314240121 in words is "ten billion, three hundred fourteen million, two hundred forty thousand, one hundred twenty-one".
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