Base | Representation |
---|---|
bin | 10011001101101011… |
… | …10101001100000001 |
3 | 222121220002122202011 |
4 | 21212311311030001 |
5 | 132111210301423 |
6 | 4423325052521 |
7 | 513423535255 |
oct | 114665651401 |
9 | 28556078664 |
10 | 10315322113 |
11 | 44138041a8 |
12 | 1bba6b7141 |
13 | c851213c5 |
14 | 6dbda4265 |
15 | 4058e6b0d |
hex | 266d75301 |
10315322113 has 2 divisors, whose sum is σ = 10315322114. Its totient is φ = 10315322112.
The previous prime is 10315322111. The next prime is 10315322123. The reversal of 10315322113 is 31122351301.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 6082128144 + 4233193969 = 77988^2 + 65063^2 .
It is an emirp because it is prime and its reverse (31122351301) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 10315322113 - 21 = 10315322111 is a prime.
Together with 10315322111, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (10315322111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5157661056 + 5157661057.
It is an arithmetic number, because the mean of its divisors is an integer number (5157661057).
Almost surely, 210315322113 is an apocalyptic number.
It is an amenable number.
10315322113 is a deficient number, since it is larger than the sum of its proper divisors (1).
10315322113 is an equidigital number, since it uses as much as digits as its factorization.
10315322113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 540, while the sum is 22.
Adding to 10315322113 its reverse (31122351301), we get a palindrome (41437673414).
The spelling of 10315322113 in words is "ten billion, three hundred fifteen million, three hundred twenty-two thousand, one hundred thirteen".
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