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10315551893 is a prime number
BaseRepresentation
bin10011001101101101…
…01101010010010101
3222121220112022221112
421212312231102111
5132111240130033
64423334024405
7513425513213
oct114666552225
928556468845
1010315551893
1144139508a9
121bba7a8105
13c851a1b7a
146dc023cb3
1540593ec48
hex266dad495

10315551893 has 2 divisors, whose sum is σ = 10315551894. Its totient is φ = 10315551892.

The previous prime is 10315551881. The next prime is 10315551913. The reversal of 10315551893 is 39815551301.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10310980849 + 4571044 = 101543^2 + 2138^2 .

It is a cyclic number.

It is not a de Polignac number, because 10315551893 - 220 = 10314503317 is a prime.

It is a super-2 number, since 2×103155518932 (a number of 21 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 10315551893.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10315551833) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5157775946 + 5157775947.

It is an arithmetic number, because the mean of its divisors is an integer number (5157775947).

Almost surely, 210315551893 is an apocalyptic number.

It is an amenable number.

10315551893 is a deficient number, since it is larger than the sum of its proper divisors (1).

10315551893 is an equidigital number, since it uses as much as digits as its factorization.

10315551893 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 81000, while the sum is 41.

The spelling of 10315551893 in words is "ten billion, three hundred fifteen million, five hundred fifty-one thousand, eight hundred ninety-three".