Base | Representation |
---|---|
bin | 11110000010001011000… |
… | …11101101001111110101 |
3 | 10122122200000011220202121 |
4 | 33001011203231033311 |
5 | 113401423014424232 |
6 | 2110024145435541 |
7 | 134361623645221 |
oct | 17010543551765 |
9 | 3578600156677 |
10 | 1031959139317 |
11 | 368719038327 |
12 | 14800103bbb1 |
13 | 7640c4cc772 |
14 | 37d38b51781 |
15 | 1bc9c380d97 |
hex | f0458ed3f5 |
1031959139317 has 2 divisors, whose sum is σ = 1031959139318. Its totient is φ = 1031959139316.
The previous prime is 1031959139287. The next prime is 1031959139333. The reversal of 1031959139317 is 7139319591301.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 744905360241 + 287053779076 = 863079^2 + 535774^2 .
It is a cyclic number.
It is not a de Polignac number, because 1031959139317 - 211 = 1031959137269 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1031959131317) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 515979569658 + 515979569659.
It is an arithmetic number, because the mean of its divisors is an integer number (515979569659).
Almost surely, 21031959139317 is an apocalyptic number.
It is an amenable number.
1031959139317 is a deficient number, since it is larger than the sum of its proper divisors (1).
1031959139317 is an equidigital number, since it uses as much as digits as its factorization.
1031959139317 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 688905, while the sum is 52.
The spelling of 1031959139317 in words is "one trillion, thirty-one billion, nine hundred fifty-nine million, one hundred thirty-nine thousand, three hundred seventeen".
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