103200130010003 has 4 divisors (see below), whose sum is σ = 111138601549248. Its totient is φ = 95261658470760.

The previous prime is 103200130009993. The next prime is 103200130010041. The reversal of 103200130010003 is 300010031002301.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 103200130010003 - 2¹⁶ = 103200129944467 is a prime.

It is a super-4 number, since 4×103200130010003⁴ (a number of 57 digits) contains 4444 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 103200130010003.

It is not an unprimeable number, because it can be changed into a prime (103200130010093) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3969235769603 + ... + 3969235769628.

It is an arithmetic number, because the mean of its divisors is an integer number (27784650387312).

Almost surely, 2^{103200130010003} is an apocalyptic number.

103200130010003 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

103200130010003 is a deficient number, since it is larger than the sum of its proper divisors (7938471539245).

103200130010003 is an equidigital number, since it uses as much as digits as its factorization.

103200130010003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7938471539244.

The product of its (nonzero) digits is 54, while the sum is 14.

Adding to 103200130010003 its reverse (300010031002301), we get a palindrome (403210161012304).

The spelling of 103200130010003 in words is "one hundred three trillion, two hundred billion, one hundred thirty million, ten thousand, three".