Base | Representation |
---|---|
bin | 10111011101110000110100… |
… | …100001011000100110100111 |
3 | 111112101212011012112101201021 |
4 | 113131300310201120212213 |
5 | 102011313311432330142 |
6 | 1003253331100512011 |
7 | 30510660003623026 |
oct | 2735606441304647 |
9 | 445355135471637 |
10 | 103200355355047 |
11 | 2a979030196605 |
12 | b6a8b0624b607 |
13 | 45779a07a4772 |
14 | 1b6acd108c8bd |
15 | bde72877d267 |
hex | 5ddc348589a7 |
103200355355047 has 2 divisors, whose sum is σ = 103200355355048. Its totient is φ = 103200355355046.
The previous prime is 103200355355003. The next prime is 103200355355063. The reversal of 103200355355047 is 740553553002301.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 103200355355047 - 231 = 103198207871399 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 103200355354994 and 103200355355012.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (103200355352047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51600177677523 + 51600177677524.
It is an arithmetic number, because the mean of its divisors is an integer number (51600177677524).
Almost surely, 2103200355355047 is an apocalyptic number.
103200355355047 is a deficient number, since it is larger than the sum of its proper divisors (1).
103200355355047 is an equidigital number, since it uses as much as digits as its factorization.
103200355355047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 945000, while the sum is 43.
The spelling of 103200355355047 in words is "one hundred three trillion, two hundred billion, three hundred fifty-five million, three hundred fifty-five thousand, forty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.066 sec. • engine limits •