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10320122023 = 191648132957
BaseRepresentation
bin10011001110010000…
…01001000010100111
3222122020010111222121
421213020021002213
5132113422401043
64424020010411
7513512406211
oct114710110247
928566114877
1010320122023
114416492472
122000230a07
13c861120a3
146dc8935b1
15406043ded
hex2672090a7

10320122023 has 8 divisors (see below), whose sum is σ = 10864275120. Its totient is φ = 9776067840.

The previous prime is 10320122009. The next prime is 10320122063. The reversal of 10320122023 is 32022102301.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 10320122023 - 213 = 10320113831 is a prime.

It is a super-2 number, since 2×103201220232 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10320121988 and 10320122006.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10320122063) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 296661 + ... + 329617.

It is an arithmetic number, because the mean of its divisors is an integer number (1358034390).

Almost surely, 210320122023 is an apocalyptic number.

10320122023 is a deficient number, since it is larger than the sum of its proper divisors (544153097).

10320122023 is a wasteful number, since it uses less digits than its factorization.

10320122023 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 49457.

The product of its (nonzero) digits is 144, while the sum is 16.

Adding to 10320122023 its reverse (32022102301), we get a palindrome (42342224324).

The spelling of 10320122023 in words is "ten billion, three hundred twenty million, one hundred twenty-two thousand, twenty-three".

Divisors: 1 19 16481 32957 313139 626183 543164317 10320122023