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1032013101131 = 9599471075073
BaseRepresentation
bin11110000010010001100…
…01100011100001001011
310122122210202201110110022
433001020301203201023
5113402030323214011
62110033354211055
7134363150423255
oct17011061434113
93578722643408
101032013101131
11368746544671
12148017123a8b
137641a74422c
1437d41d9acd5
151bca1e8e8db
hexf048c6384b

1032013101131 has 4 divisors (see below), whose sum is σ = 1032015136152. Its totient is φ = 1032011066112.

The previous prime is 1032013101121. The next prime is 1032013101139. The reversal of 1032013101131 is 1311013102301.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1032013101131 - 214 = 1032013084747 is a prime.

It is a super-2 number, since 2×10320131011312 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1032013101139) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 422411 + ... + 1497483.

It is an arithmetic number, because the mean of its divisors is an integer number (258003784038).

Almost surely, 21032013101131 is an apocalyptic number.

1032013101131 is a deficient number, since it is larger than the sum of its proper divisors (2035021).

1032013101131 is an equidigital number, since it uses as much as digits as its factorization.

1032013101131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2035020.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 1032013101131 its reverse (1311013102301), we get a palindrome (2343026203432).

The spelling of 1032013101131 in words is "one trillion, thirty-two billion, thirteen million, one hundred one thousand, one hundred thirty-one".

Divisors: 1 959947 1075073 1032013101131