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103215060147 = 334405020049
BaseRepresentation
bin110000000100000011…
…0001101010010110011
3100212102020100022122110
41200020012031102303
53142341023411042
6115225532540403
710312523351463
oct1401006152263
9325366308573
10103215060147
113a856235401
1218006621703
13996b9220b4
144dd2049ba3
152a4161009c
hex180818d4b3

103215060147 has 4 divisors (see below), whose sum is σ = 137620080200. Its totient is φ = 68810040096.

The previous prime is 103215060119. The next prime is 103215060149. The reversal of 103215060147 is 741060512301.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 103215060147 - 211 = 103215058099 is a prime.

It is a super-2 number, since 2×1032150601472 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (103215060149) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17202510022 + ... + 17202510027.

It is an arithmetic number, because the mean of its divisors is an integer number (34405020050).

Almost surely, 2103215060147 is an apocalyptic number.

103215060147 is a deficient number, since it is larger than the sum of its proper divisors (34405020053).

103215060147 is an equidigital number, since it uses as much as digits as its factorization.

103215060147 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 34405020052.

The product of its (nonzero) digits is 5040, while the sum is 30.

Adding to 103215060147 its reverse (741060512301), we get a palindrome (844275572448).

The spelling of 103215060147 in words is "one hundred three billion, two hundred fifteen million, sixty thousand, one hundred forty-seven".

Divisors: 1 3 34405020049 103215060147