Base | Representation |
---|---|
bin | 10111011110000101000110… |
… | …011001100001100110010111 |
3 | 111112110221100201121010022110 |
4 | 113132011012121201212113 |
5 | 102012142410302333421 |
6 | 1003311331505402103 |
7 | 30512360416236021 |
oct | 2736050631414627 |
9 | 445427321533273 |
10 | 103222130121111 |
11 | 2a987294504641 |
12 | b6b1182639333 |
13 | 4579a60a75921 |
14 | 1b6bd98d5d011 |
15 | be00a021aa76 |
hex | 5de146661997 |
103222130121111 has 4 divisors (see below), whose sum is σ = 137629506828152. Its totient is φ = 68814753414072.
The previous prime is 103222130121067. The next prime is 103222130121157. The reversal of 103222130121111 is 111121031222301.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 103222130121111 - 213 = 103222130112919 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (103222130121511) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17203688353516 + ... + 17203688353521.
It is an arithmetic number, because the mean of its divisors is an integer number (34407376707038).
Almost surely, 2103222130121111 is an apocalyptic number.
103222130121111 is a deficient number, since it is larger than the sum of its proper divisors (34407376707041).
103222130121111 is an equidigital number, since it uses as much as digits as its factorization.
103222130121111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 34407376707040.
The product of its (nonzero) digits is 144, while the sum is 21.
Adding to 103222130121111 its reverse (111121031222301), we get a palindrome (214343161343412).
The spelling of 103222130121111 in words is "one hundred three trillion, two hundred twenty-two billion, one hundred thirty million, one hundred twenty-one thousand, one hundred eleven".
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