Base | Representation |
---|---|
bin | 10011001110100110… |
… | …01010011011100101 |
3 | 222122102120022022220 |
4 | 21213103022123211 |
5 | 132120142330201 |
6 | 4424201542553 |
7 | 513546101601 |
oct | 114723123345 |
9 | 28572508286 |
10 | 10323011301 |
11 | 44180861a9 |
12 | 20011a4a59 |
13 | c868b4215 |
14 | 6dd006501 |
15 | 406415036 |
hex | 2674ca6e5 |
10323011301 has 4 divisors (see below), whose sum is σ = 13764015072. Its totient is φ = 6882007532.
The previous prime is 10323011243. The next prime is 10323011311. The reversal of 10323011301 is 10311032301.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 10311032301 = 3 ⋅3437010767.
It is a cyclic number.
It is not a de Polignac number, because 10323011301 - 27 = 10323011173 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (10323011311) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1720501881 + ... + 1720501886.
It is an arithmetic number, because the mean of its divisors is an integer number (3441003768).
Almost surely, 210323011301 is an apocalyptic number.
It is an amenable number.
10323011301 is a deficient number, since it is larger than the sum of its proper divisors (3441003771).
10323011301 is an equidigital number, since it uses as much as digits as its factorization.
10323011301 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3441003770.
The product of its (nonzero) digits is 54, while the sum is 15.
Adding to 10323011301 its reverse (10311032301), we get a palindrome (20634043602).
The spelling of 10323011301 in words is "ten billion, three hundred twenty-three million, eleven thousand, three hundred one".
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