Base | Representation |
---|---|
bin | 10011001110100110… |
… | …10001100010110001 |
3 | 222122102121210021212 |
4 | 21213103101202301 |
5 | 132120144243213 |
6 | 4424202325505 |
7 | 513546252536 |
oct | 114723214261 |
9 | 28572553255 |
10 | 10323040433 |
11 | 44180a6082 |
12 | 20011b9895 |
13 | c868c4564 |
14 | 6dd012d8d |
15 | 40641d9a8 |
hex | 2674d18b1 |
10323040433 has 8 divisors (see below), whose sum is σ = 10500399360. Its totient is φ = 10145761360.
The previous prime is 10323040417. The next prime is 10323040439. The reversal of 10323040433 is 33404032301.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 10323040433 - 24 = 10323040417 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 10323040399 and 10323040408.
It is not an unprimeable number, because it can be changed into a prime (10323040439) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 278816 + ... + 313662.
It is an arithmetic number, because the mean of its divisors is an integer number (1312549920).
Almost surely, 210323040433 is an apocalyptic number.
It is an amenable number.
10323040433 is a deficient number, since it is larger than the sum of its proper divisors (177358927).
10323040433 is an equidigital number, since it uses as much as digits as its factorization.
10323040433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 39927.
The product of its (nonzero) digits is 2592, while the sum is 23.
Adding to 10323040433 its reverse (33404032301), we get a palindrome (43727072734).
The spelling of 10323040433 in words is "ten billion, three hundred twenty-three million, forty thousand, four hundred thirty-three".
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