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103231002013 = 313330032323
BaseRepresentation
bin110000000100100001…
…1000001010110011101
3100212110100100020202221
41200021003001112131
53142404114031023
6115231302345341
710313106016306
oct1401103012635
9325410306687
10103231002013
113a8642337a7
121800ba2b251
139972014359
144dd41d97ad
152a42c0d85d
hex18090c159d

103231002013 has 4 divisors (see below), whose sum is σ = 106561034368. Its totient is φ = 99900969660.

The previous prime is 103231001987. The next prime is 103231002031. The reversal of 103231002013 is 310200132301.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-103231002013 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (103231006013) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1665016131 + ... + 1665016192.

It is an arithmetic number, because the mean of its divisors is an integer number (26640258592).

Almost surely, 2103231002013 is an apocalyptic number.

It is an amenable number.

103231002013 is a deficient number, since it is larger than the sum of its proper divisors (3330032355).

103231002013 is an equidigital number, since it uses as much as digits as its factorization.

103231002013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3330032354.

The product of its (nonzero) digits is 108, while the sum is 16.

Adding to 103231002013 its reverse (310200132301), we get a palindrome (413431134314).

The spelling of 103231002013 in words is "one hundred three billion, two hundred thirty-one million, two thousand, thirteen".

Divisors: 1 31 3330032323 103231002013