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1032313212131 is a prime number
BaseRepresentation
bin11110000010110101010…
…10011000110011100011
310122200120200102200100112
433001122222120303203
5113403134140242011
62110123234441535
7134403453344405
oct17013252306343
93580520380315
101032313212131
1136888a994493
1214809b7332ab
13764679806c6
1437d6db9cb75
151bcbd4c158b
hexf05aa98ce3

1032313212131 has 2 divisors, whose sum is σ = 1032313212132. Its totient is φ = 1032313212130.

The previous prime is 1032313212121. The next prime is 1032313212163. The reversal of 1032313212131 is 1312123132301.

1032313212131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1032313212131 is a prime.

It is a super-2 number, since 2×10323132121312 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1032313212097 and 1032313212106.

It is not a weakly prime, because it can be changed into another prime (1032313212101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 516156606065 + 516156606066.

It is an arithmetic number, because the mean of its divisors is an integer number (516156606066).

Almost surely, 21032313212131 is an apocalyptic number.

1032313212131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1032313212131 is an equidigital number, since it uses as much as digits as its factorization.

1032313212131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 648, while the sum is 23.

Adding to 1032313212131 its reverse (1312123132301), we get a palindrome (2344436344432).

The spelling of 1032313212131 in words is "one trillion, thirty-two billion, three hundred thirteen million, two hundred twelve thousand, one hundred thirty-one".