Base | Representation |
---|---|
bin | 10111011110001111010110… |
… | …000111110011111000111101 |
3 | 111112111222202102022111101111 |
4 | 113132033112013303320331 |
5 | 102012332423110044013 |
6 | 1003320351255442021 |
7 | 30513230142051436 |
oct | 2736172607637075 |
9 | 445458672274344 |
10 | 103233131331133 |
11 | 2a990a1a399551 |
12 | b6b3332986311 |
13 | 457aac5004c5b |
14 | 1b6c72006648d |
15 | be04e5e4873d |
hex | 5de3d61f3e3d |
103233131331133 has 2 divisors, whose sum is σ = 103233131331134. Its totient is φ = 103233131331132.
The previous prime is 103233131331101. The next prime is 103233131331241. The reversal of 103233131331133 is 331133131332301.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 71212720970169 + 32020410360964 = 8438763^2 + 5658658^2 .
It is an emirp because it is prime and its reverse (331133131332301) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 103233131331133 - 25 = 103233131331101 is a prime.
It is a super-3 number, since 3×1032331313311333 (a number of 43 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 103233131331095 and 103233131331104.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (103233131301133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51616565665566 + 51616565665567.
It is an arithmetic number, because the mean of its divisors is an integer number (51616565665567).
Almost surely, 2103233131331133 is an apocalyptic number.
It is an amenable number.
103233131331133 is a deficient number, since it is larger than the sum of its proper divisors (1).
103233131331133 is an equidigital number, since it uses as much as digits as its factorization.
103233131331133 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13122, while the sum is 31.
Adding to 103233131331133 its reverse (331133131332301), we get a palindrome (434366262663434).
The spelling of 103233131331133 in words is "one hundred three trillion, two hundred thirty-three billion, one hundred thirty-one million, three hundred thirty-one thousand, one hundred thirty-three".
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