Base | Representation |
---|---|
bin | 10111011110010001100101… |
… | …111011011010011010001111 |
3 | 111112112012222120011210001222 |
4 | 113132101211323122122033 |
5 | 102012402343231001033 |
6 | 1003321430523353555 |
7 | 30513344006312042 |
oct | 2736214573323217 |
9 | 445465876153058 |
10 | 103235544000143 |
11 | 2a991a48274485 |
12 | b6b38a69828bb |
13 | 457b0bab08259 |
14 | 1b6c8ac662c59 |
15 | be05d7b73598 |
hex | 5de465eda68f |
103235544000143 has 2 divisors, whose sum is σ = 103235544000144. Its totient is φ = 103235544000142.
The previous prime is 103235544000101. The next prime is 103235544000217. The reversal of 103235544000143 is 341000445532301.
It is a weak prime.
It is an emirp because it is prime and its reverse (341000445532301) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-103235544000143 is a prime.
It is a super-2 number, since 2×1032355440001432 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (103235544000643) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51617772000071 + 51617772000072.
It is an arithmetic number, because the mean of its divisors is an integer number (51617772000072).
Almost surely, 2103235544000143 is an apocalyptic number.
103235544000143 is a deficient number, since it is larger than the sum of its proper divisors (1).
103235544000143 is an equidigital number, since it uses as much as digits as its factorization.
103235544000143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 86400, while the sum is 35.
Adding to 103235544000143 its reverse (341000445532301), we get a palindrome (444235989532444).
The spelling of 103235544000143 in words is "one hundred three trillion, two hundred thirty-five billion, five hundred forty-four million, one hundred forty-three", and thus it is an aban number.
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