Base | Representation |
---|---|
bin | 1001011000111100000011… |
… | …0111111100111011100101 |
3 | 1100112222011020222221011121 |
4 | 2112033000313330323211 |
5 | 2323122114312232003 |
6 | 33542444412133541 |
7 | 2113613251446235 |
oct | 226170067747345 |
9 | 40488136887147 |
10 | 10324042305253 |
11 | 3320446809086 |
12 | 11a8a50a672b1 |
13 | 59b725c76351 |
14 | 27998735dcc5 |
15 | 12d84319ccbd |
hex | 963c0dfcee5 |
10324042305253 has 4 divisors (see below), whose sum is σ = 10341277768800. Its totient is φ = 10306806841708.
The previous prime is 10324042305251. The next prime is 10324042305259. The reversal of 10324042305253 is 35250324042301.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 10324042305253 - 21 = 10324042305251 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (10324042305251) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8617730875 + ... + 8617732072.
It is an arithmetic number, because the mean of its divisors is an integer number (2585319442200).
Almost surely, 210324042305253 is an apocalyptic number.
It is an amenable number.
10324042305253 is a deficient number, since it is larger than the sum of its proper divisors (17235463547).
10324042305253 is an equidigital number, since it uses as much as digits as its factorization.
10324042305253 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 17235463546.
The product of its (nonzero) digits is 86400, while the sum is 34.
Adding to 10324042305253 its reverse (35250324042301), we get a palindrome (45574366347554).
The spelling of 10324042305253 in words is "ten trillion, three hundred twenty-four billion, forty-two million, three hundred five thousand, two hundred fifty-three".
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