1032441343431 has 4 divisors (see below), whose sum is σ = 1376588457912. Its totient is φ = 688294228952.

The previous prime is 1032441343429. The next prime is 1032441343433. The reversal of 1032441343431 is 1343431442301.

1032441343431 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (1032441343429) and next prime (1032441343433).

It is a cyclic number.

It is not a de Polignac number, because 1032441343431 - 2¹ = 1032441343429 is a prime.

It is a super-2 number, since 2×1032441343431² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1032441343392 and 1032441343401.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1032441343433) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 172073557236 + ... + 172073557241.

It is an arithmetic number, because the mean of its divisors is an integer number (344147114478).

Almost surely, 2^{1032441343431} is an apocalyptic number.

1032441343431 is a deficient number, since it is larger than the sum of its proper divisors (344147114481).

1032441343431 is an equidigital number, since it uses as much as digits as its factorization.

1032441343431 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 344147114480.

The product of its (nonzero) digits is 41472, while the sum is 33.

Adding to 1032441343431 its reverse (1343431442301), we get a palindrome (2375872785732).

The spelling of 1032441343431 in words is "one trillion, thirty-two billion, four hundred forty-one million, three hundred forty-three thousand, four hundred thirty-one".