Base | Representation |
---|---|
bin | 110000000101011010… |
… | …1111000110000111111 |
3 | 100212112110000001211202 |
4 | 1200022311320300333 |
5 | 3142434321112112 |
6 | 115234300010115 |
7 | 10313622660524 |
oct | 1401265706077 |
9 | 325473001752 |
10 | 103261113407 |
11 | 3a87a22a951 |
12 | 18019b3093b |
13 | 9978327c4a |
14 | 4dd81d714b |
15 | 2a456aa6c2 |
hex | 180ad78c3f |
103261113407 has 2 divisors, whose sum is σ = 103261113408. Its totient is φ = 103261113406.
The previous prime is 103261113377. The next prime is 103261113457. The reversal of 103261113407 is 704311162301.
It is a weak prime.
It is an emirp because it is prime and its reverse (704311162301) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-103261113407 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 103261113407.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (103261113457) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51630556703 + 51630556704.
It is an arithmetic number, because the mean of its divisors is an integer number (51630556704).
Almost surely, 2103261113407 is an apocalyptic number.
103261113407 is a deficient number, since it is larger than the sum of its proper divisors (1).
103261113407 is an equidigital number, since it uses as much as digits as its factorization.
103261113407 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3024, while the sum is 29.
Adding to 103261113407 its reverse (704311162301), we get a palindrome (807572275708).
The spelling of 103261113407 in words is "one hundred three billion, two hundred sixty-one million, one hundred thirteen thousand, four hundred seven".
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