Base | Representation |
---|---|
bin | 10111011111001101101001… |
… | …100111001000000000111111 |
3 | 111112202101102201112020120102 |
4 | 113133031221213020000333 |
5 | 102014431430224101343 |
6 | 1003411213452511315 |
7 | 30521116022650601 |
oct | 2737155147100077 |
9 | 445671381466512 |
10 | 103300030300223 |
11 | 2aa0732a095159 |
12 | b7042a317b53b |
13 | 45841c6b53273 |
14 | 1b71a68c97171 |
15 | be210e1aa3b8 |
hex | 5df3699c803f |
103300030300223 has 2 divisors, whose sum is σ = 103300030300224. Its totient is φ = 103300030300222.
The previous prime is 103300030300213. The next prime is 103300030300343. The reversal of 103300030300223 is 322003030003301.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 103300030300223 - 222 = 103300026105919 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 103300030300195 and 103300030300204.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (103300030300213) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51650015150111 + 51650015150112.
It is an arithmetic number, because the mean of its divisors is an integer number (51650015150112).
Almost surely, 2103300030300223 is an apocalyptic number.
103300030300223 is a deficient number, since it is larger than the sum of its proper divisors (1).
103300030300223 is an equidigital number, since it uses as much as digits as its factorization.
103300030300223 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 972, while the sum is 20.
Adding to 103300030300223 its reverse (322003030003301), we get a palindrome (425303060303524).
The spelling of 103300030300223 in words is "one hundred three trillion, three hundred billion, thirty million, three hundred thousand, two hundred twenty-three".
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