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1033011131293 is a prime number
BaseRepresentation
bin11110000100001000100…
…00101111001110011101
310122202101022200122110101
433002010100233032131
5113411101322200133
62110320405341101
7134426656511221
oct17020420571635
93582338618411
101033011131293
11369108942489
12148255407791
137654944191b
1437dd8754781
151bd0e8d237d
hexf08442f39d

1033011131293 has 2 divisors, whose sum is σ = 1033011131294. Its totient is φ = 1033011131292.

The previous prime is 1033011131261. The next prime is 1033011131333. The reversal of 1033011131293 is 3921311103301.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1031813071524 + 1198059769 = 1015782^2 + 34613^2 .

It is a cyclic number.

It is not a de Polignac number, because 1033011131293 - 25 = 1033011131261 is a prime.

It is a super-2 number, since 2×10330111312932 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1033011131213) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 516505565646 + 516505565647.

It is an arithmetic number, because the mean of its divisors is an integer number (516505565647).

Almost surely, 21033011131293 is an apocalyptic number.

It is an amenable number.

1033011131293 is a deficient number, since it is larger than the sum of its proper divisors (1).

1033011131293 is an equidigital number, since it uses as much as digits as its factorization.

1033011131293 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1458, while the sum is 28.

Adding to 1033011131293 its reverse (3921311103301), we get a palindrome (4954322234594).

The spelling of 1033011131293 in words is "one trillion, thirty-three billion, eleven million, one hundred thirty-one thousand, two hundred ninety-three".