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10331022113 is a prime number
BaseRepresentation
bin10011001111100011…
…01110001100100001
3222122222122022002122
421213301232030201
5132124220201423
64425045354025
7514004144666
oct114761561441
928588568078
1010331022113
114421657905
122003a08915
13c8845a549
147000cda6d
15406e988c8
hex267c6e321

10331022113 has 2 divisors, whose sum is σ = 10331022114. Its totient is φ = 10331022112.

The previous prime is 10331022103. The next prime is 10331022157. The reversal of 10331022113 is 31122013301.

10331022113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8847847969 + 1483174144 = 94063^2 + 38512^2 .

It is a cyclic number.

It is not a de Polignac number, because 10331022113 - 210 = 10331021089 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10331022091 and 10331022100.

It is not a weakly prime, because it can be changed into another prime (10331022103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5165511056 + 5165511057.

It is an arithmetic number, because the mean of its divisors is an integer number (5165511057).

Almost surely, 210331022113 is an apocalyptic number.

It is an amenable number.

10331022113 is a deficient number, since it is larger than the sum of its proper divisors (1).

10331022113 is an equidigital number, since it uses as much as digits as its factorization.

10331022113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 10331022113 its reverse (31122013301), we get a palindrome (41453035414).

The spelling of 10331022113 in words is "ten billion, three hundred thirty-one million, twenty-two thousand, one hundred thirteen".