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10331130013 is a prime number
BaseRepresentation
bin10011001111100100…
…01000100010011101
3222122222211210002221
421213302020202131
5132124232130023
64425051545341
7514005104401
oct114762104235
928588753087
1010331130013
114421720986
122003a5b251
13c884976a9
1470011b101
15406eba85d
hex267c8889d

10331130013 has 2 divisors, whose sum is σ = 10331130014. Its totient is φ = 10331130012.

The previous prime is 10331130001. The next prime is 10331130031. The reversal of 10331130013 is 31003113301.

Together with next prime (10331130031) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9749982564 + 581147449 = 98742^2 + 24107^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10331130013 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10331130913) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5165565006 + 5165565007.

It is an arithmetic number, because the mean of its divisors is an integer number (5165565007).

Almost surely, 210331130013 is an apocalyptic number.

It is an amenable number.

10331130013 is a deficient number, since it is larger than the sum of its proper divisors (1).

10331130013 is an equidigital number, since it uses as much as digits as its factorization.

10331130013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 81, while the sum is 16.

Adding to 10331130013 its reverse (31003113301), we get a palindrome (41334243314).

The spelling of 10331130013 in words is "ten billion, three hundred thirty-one million, one hundred thirty thousand, thirteen".